If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. I suppose that Euler_Project are for getting better at programming, I don't think you should handle answers as easily as you did. Solution Obvious solution. ... but it was the Project Euler forums that showed me the formula to do it. Problem 1: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Submissions. The sum of these multiples is 23. I solve Project Euler problems to practice and extend my math and programming skills, all while having fun at the same time. Problem. Project Euler solutions Introduction. If a box contains twenty-one coloured discs, composed of fifteen blue discs and six red discs, and two discs were taken at random, it can be seen that the probability of taking two blue discs, P(BB) = (15/21)×(14/20) = 1/2. – Fabinout Jan 29 '14 at 16:24 May 3, 2011 Programming C++, Code, Project Euler Rian. Project Euler Problem 1 Statement. I'm learning C++ and currently doing Project Euler challenges. Discussions. The sum of these multiples is 23. Question 1: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. A more mathematical way to solve the first problem in the project Euler archives. Since you have a generalized solution, you should provide your generalized specification of the problem. Make an attempt, then come back with specific questions about any difficulties you're having. The first challenge is the following. The sum of these multiples is 23. If we list all the natural numbers below that are multiples of or , we get and . Here I make my solutions publicly available for other enthusiasts to learn from and to critique. The series, 1 1 + 2 2 + 3 3 + … + 10 10 = 10405071317.. Find the last ten digits of the series, 1 1 + 2 2 + 3 3 + … + 1000 1000.. Problem 48 of Project Euler has the nice and simple description. Find the sum of all the multiples of 3 or 5 below 1000. Project Euler is a teaching resource. Please be sure to answer the question. The sum of these multiples is 23. If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Especially when somebody already pointed out the problem in her code. Active today. This problem is a programming version of Problem 1 from projecteuler.net. Project Euler (projecteuler.net) is a series of challenging mathematical/computer programming problems that will require more than just mathematical insights to solve. C++ solution to Project Euler Problem 1. Ask Question Asked today. Viewed 11 times 1 $\begingroup$ Okay so the problem itself is really simple, If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. 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